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Q:

Efficiently generate random non-repeating letters in Lua

I need a way to randomly generate letters for a text string with the following criteria:

Each letter should be different
There should be no repeated letters

I’ve tried several variations of this code which will generate letters between a and z, but they are all found to have a repeating letter:
function shuffledLetters(n)
for i = 1,n do
local r = math.random(26)
local e = string.char(string.byte(r))
end
end

How would you perform this in a more efficient manner?

A:

function shuffleletters(n)
local letters = {}
for i = 1, n do
letters[i] = i
end
table.sort(letters)
while true do
local r = math.random(n)
local i = letters[r]
letters[i] = nil
table.remove(letters, i)
end
return ”.join(tostring(i) for i in letters)
end

The algorithm is simple. Select a random index in the table, and if it’s not nil, use it; otherwise, “swap” it with a nil.
This is not very efficient. For each application of the algorithm, the lookup table needs to be created, and then recreated with every call. If the input sequence is very large, then the table creation may slow things down. An other solution is to preallocate a table and then make only one linear pass through the table to find the first non-nil entry.
Edit: forgot to
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